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js 相差天数

function getTime2Time($time1, $time2){var time1 = arguments[0], time2 = arguments[1];time1 = Date.parse(time1)/1000;time2 = Date.parse(time2)/1000;var time_ = time1 - time2;return (time_/(3600*24));}document.write(getTime2Time(...

var date1=new Date(); //开始时间 var date2=new Date(); //结束时间 var date3=date2.getTime()-date1.getTime() //时间差的毫秒数 ------------------------------ //计算出相差天数 var days=Math.floor(date3/(24*3600*1000))

1.把开始时间和结束时间保存 var dateFrom = new Date(strFrom); var dateTo = new Date(strTo); 2.计算时间差 var diff = dateTo.valueOf() - dateFrom.valueOf(); 3.时间差转换为天数 var diff_day = parseInt(diff/(1000*60*60*24));

function DateDiff(sDate1, sDate2){ //sDate1和sDate2是2002-12-18格式 var aDate, oDate1, oDate2, iDays aDate = sDate1.split("-") oDate1 = new Date(aDate[1] + '-' + aDate[2] + '-' + aDate[0]) //转换为12-18-2002格式 aDate = sDate2....

var time = date2.getTime() - date1.getTime() ; //日期的long型值之差 两个日期相差 Math.floor(time/(24*60*60*1000)) 天

function getTime2Time($time1, $time2) { var time1 = arguments[0], time2 = arguments[1]; time1 = Date.parse(time1)/1000; time2 = Date.parse(time2)/1000; var time_ = time1 - time2; return (time_/(3600*24)); } document.write(getTi...

俺知道地主哥不是学js的啦不用强调的啦不过有异曲同工之妙的啦var d1=new Date('2010-01-01');var d2=new Date('2010-02-02');(d2-d1)/(24*60*60*1000)

function show(){ var menu1=document.myform.menu1; var menu2=document.myform.menu2; var menu3=document.myform.menu3; var g=menu1.options[menu1.selectedIndex].value; var e=menu2.options[menu2.selectedIndex].value; var a=menu3.opt...

var start = $("#startDate").val();var end = $("#endDate").val();var date1 = new Date(start.replace(/[^\/\d]+/g,"/")+",0:0:0");var date2 = new Date(end.replace(/[^\/\d]+/g,"/")+",0:0:0");date1.setMonth(date1.getMonth() + 2);if (...

相差的毫秒数 / 1000 / 60 / 60 /24

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