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sql查询按两个字段查询重复记录

select * from shiyan003 a where exists (select 1 from (select xm, sfzhm from shiyan003 group by xm, sfzhm having count(*) > 1) s where s.xm = a.xm and s.sfzhm = a.sfzhm)

selectid,name,memo fromA whereidin(selectidfromAgroupbyidhavingcount(1)>=2) 1查询 abcd相同的记录: select * from F where a=b and b=c and c=d 2查询有重复数据的记录 select * from F group by a,b,c,d having count(*)>1 3取出数据过滤...

两种方法,一种是查询重复的数据,只查询重复记录,不管其余信息,如ID什么的: select uid, time from ztest GROUP BY uid, time having count(*)>1;查出结果是 uid time 1 1 还有一种是查询你指定信息,可以查询出ID信息: select distinct a....

select * from CJB a join ( select XH,KCMC from CJB group by XH,KCMC having count(*)>1) b on a.XH=b.XH and a.KCMC=b.KCMC order by a.KCMC ,a.XH

select a,b,c,d,e,f from a group by a,b,c,d,e,f having count(*)>1

查看可用如下方法: 1、创建测试表,插入数据: create table product(id int,name varchar(10),totol int)insert into product values (1,'香蕉',100)insert into product values (2,'橘子',67)insert into product values (3,'葡萄',89)insert...

select * from 表 where 字段 in( select 字段 from 表 group by 字段 having count(1)>1)

可用group by……having来实现。 可做如下测试: 1、创建表插入数据: create table test(id int,name varchar(10))insert into test values (1,'张三')insert into test values (2,'李四')insert into test values (3,'张三')insert into test va...

需要用连接查询来处理。 如有以下2张表: 查询2张表id和name字段内容完全相同的内容,可用如下语句: select a.* from test a,test1 b where a.id=b.id and a.name=b.name;结果: 说明,两表连接where条件要写上关联条件,因为提问是两个字段完...

是要同时查出两个表所有的记录,还是这个字段相同的记录? 1.同时查出两个表所有的记录: select 字段 from table1 union select 字段 from table2 2.这个字段相同的记录 select * from table1,table2 where table1.字段 = table2.字段

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